If f0≤x≤1, then cos−12x2−1 equals
2cos−1x
π−2cos−1x
2π−2cos−1x
none of these
Let cos−1x=θ. Then, x=cosθ.
Also, 0≤x≤1⇒0≤cosθ≤1⇒0≤θ≤π2
Now,
cos−12x2−1= cos−12cos2θ−1
= cos−1(cos2θ)=2θ=2cos−1x [∵0≤2θ≤π]