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Q.

If f(x)=[7−(x−5)3]17,  then f−1(x) =

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a

7−x73+5

b

7−x7+5

c

7+x73−5

d

7−x73−5

answer is A.

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Detailed Solution

f−1(x)=y⇔x=f(y)⇔x=[7−(y−5)3]17⇔x7=7−(y−5)3 ⇔(y−5)3=7−x7⇔y−5=(7−x7)13⇔y=7−x73+5  ⇔f−1(x)=7−x73+5
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