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Questions  

 If f(x)=ax2+bx+c and f(1)4,f(1)0 and f(3)5, then the least value of a is 

a
14
b
18
c
13
d
-13

detailed solution

Correct option is B

f(−1)≥−4----(1)⇒a−b+c≥−4f(1)≤0⇒a+b+c≤0⇒ −a−b−c≥0---(2)f(3)≥5 and 9a+3b+c≥5----(3) From (i) + (ii) ⇒−2b≥−4----(4) From (ii) +(iii)+(iv)⇒8a≥1 ⇒ a≥1/8

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