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$If f (x) = \frac{x^{2} - bx + 25}{x^{2} - 7 x + 10} for x \neq 5$ is continuous at x = 5, then the value of f(5) is

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Correct option is A

fx=x2-bx+25x2-7x+10 , x≠5 fx is continuous at x=5 only if limx→5 x2-bx+25x2-7x+10 is finite.Now, x2-7x+10→0 when x→5.Then we must have x2-bx+25→0 for which b=10.Hence, limx→5 x2-10x+25x2-7x+10= limx→5 x-5x-2=0.

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If fx=x2-bx+25x2-7x+10 for x≠5 is continuous at x = 5, then the value of f(5) is

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$If f (x) = \frac{x^{2} - bx + 25}{x^{2} - 7 x + 10} for x \neq 5$ is continuous at x = 5, then the value of f(5) is