If fx=xcosxex6sin5xx4secxtan3x1020, then the value of ∫−π2π2 fxdx =
Given that fx=xcosxex6sin5xx4secxtan3x1020⇒f-x=−xcosxex6−sin5xx4secx−tan3x1020=−f(x)∴f(x) is an odd function ∴∫−π2π2 f(x)dx=0 ∵∫−aa f(x)dx=0, when f(x) is odd function
Therefore, the correct answer is 0000.00