If fx=xcos⁡xex6sin5⁡xx4sec⁡xtan3⁡x1020, then the value of ∫−π2π2 fxdx =

Given that fx=xcos⁡xex6sin5⁡xx4sec⁡xtan3⁡x1020⇒f-x=−xcos⁡xex6−sin5⁡xx4sec⁡x−tan3⁡x1020=−f(x)∴f(x) is an odd function ∴∫−π2π2 f(x)dx=0 ∵∫−aa f(x)dx=0, when f(x) is odd function Therefore, the correct answer is 0000.00