If f(x)=(x+1)cotx is continuous at x=0, then f(0) is
1
e
1e
none of these.
limx→0f(x)=limx→01+x 1x.xcotx=elimx→0xcotx =elimx→0xtanx=e1=e Since f(x) is continuous at x=0, ∴f(0)=e.