If f(x)=(x+1)cot⁡x is continuous at x=0, then f(0) is

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none of these.

answer is C.

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Detailed Solution

limx→0f(x)=limx→01+x 1x.xcotx=elimx→0xcotx =elimx→0xtanx=e1=e Since f(x) is continuous at x=0, ∴f(0)=e.

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