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If $F (x) = \int_{3}^{x} (2 + \frac{d}{d t} \cos t) d t$ then $F^{'} (\frac{π}{6})$ is equal to

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Correct option is D

F(x)=∫3x (2−sin⁡ t)dt so F′(x)=2−sin⁡ x.Thus F′(π/6)=2−1/2=3/2.

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If F(x)=∫3x 2+ddtcos⁡ tdt then F′π6 is equal to

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If $F (x) = \int_{3}^{x} (2 + \frac{d}{d t} \cos t) d t$ then $F^{'} (\frac{π}{6})$ is equal to