If f(x)=x3e1/x+42−e1/x,x≠00,x=0, then f(x) is

Lf1(0)=ltf(0−h)−f(0)−h=ltn→0−h3e−1/h+42−e−1/h−0−1h=2Rf1(0)=lth→0⁡f(0+h)−f(0)h=lth→0h3e1/h+42−e1/h−01h=lth→0⁡3+4e−1/h2e−1/h−1=−3 Since Lf1(0)≠Rf1(0)∴f(x) is not differentiable at x=0 . But f(x) is continuous at x=0