Questions
a
7
b
8
c
9
d
10
detailed solution
Correct option is C
Let x2−6x+6=x2−4x+4Then x = 1 Putting x=1 in the given relation, we get f(1)=1 . For x2−6x+6=1,x=1 or 5 For x2−4x+4=1,x=1 or 3 Put x=3 and 5 in the given relation. f(−3)+f(1)=6⇒f(−3)=5 and f(1)+f(9)=10⇒f(9)=9∴ f(−3)+f(9)−5f(1)=9Talk to our academic expert!
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be an even function for all Then the sum of all possible values of a is (where [.] and {.} denote greatest integer function and fractional part function, respectively)
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