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If $f (x) = 1 + 3^{x} \log 3$ and $F (x)$ be its antiderivative which assume the value $7$ for $x = 2 .$ The value of $x$ for which the curve $F (x)$ cuts the abscissa axis is

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Correct option is B

F(x)=∫f(x)dx+C=x+3x+C but F(2)=7 so 7=2+9+C⇒C=−4. Hence F(x)=x+3x−4 Now F(x)=0⇒x=1

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If f(x)=1+3xlog⁡3 and F(x) be its antiderivative which assume the value 7 for x = 2. The value of x for which the curve F(x) cuts the abscissa axis is

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If $f (x) = 1 + 3^{x} \log 3$ and $F (x)$ be its antiderivative which assume the value $7$ for $x = 2 .$ The value of $x$ for which the curve $F (x)$ cuts the abscissa axis is