If f(x)=xnsin1x,x≠0 is continuous but not differentiable at x=0 then x∈

f is continuous at x=0 then Ltx→0   fx=f0       ⇒Ltx→0     xnsin1x=0      ⇒x>0f is not differentiable at x=0 then Ltx→0f(x)-f(0)x-0 does not exist Lx→0xnsin1x-0x does not exists ⇒x≤1