First slide
Introduction to real valued functions
Question

If f(x)=x2sinπx2xxx<1x1then f(x) is

Moderate
Solution

Here, f(x)=xx,x1       =    x2sinπx2,1<x<1,               =xx,x1 f(-x)=-x-x,-x-1x2sin(-πx2),-1<-x<1-x-x,-x1  =-f(x)

 

 

 -f(x)=f(x) for all x. Also, none of the pieces of definition are periodic.

 

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