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Q.

If f(x)=(4−(x−7)3)15 , thenf−1(x)=

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a

(4+(7−x3))15

b

4−x53+7

c

4−x153−7

d

4−x+73

answer is B.

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Detailed Solution

y=(4−(x−7)3)1/5 ⇒  y5=4−(x−7)3 ⇒  (x−7)3=4−y5 ∴  x=7+4−y53 ∴f−1(x)=7+4−y53
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If f(x)=(4−(x−7)3)15 , thenf−1(x)=