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Q.

If f(x)=(4−(x−5)3)15, then f−1(x)=

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a

(4+(5−x)3)15

b

4−x53+5

c

4−x15−5

d

4−x3+5

answer is B.

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Detailed Solution

f(x)=(4−(x−5)3)15=y ⇒ 4 -x-5 3 =y5    ⇒ 4- y5=x-53   ⇒ x =5+4-y513⇒f−1(x)=4−x53+5
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