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$If f (x) = | x - 1 | - [x] (Where [X] is greatest integer less than or equal to x) then$

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f(1+)=−1;f(1−)=0

f(1+)=0=f(1−)

limx→1 f(x) exists

Cannot say any thing

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detailed solution

Correct option is A

f1(1+)=x−1−1=x−2=1−2=−1f11−=−(x−1)−0 =−x+1 =−1+1 =0

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If f(x)=|x−1|−[x] (Where [X] is greatest integer less than or equal to x)then

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$If f (x) = | x - 1 | - [x] (Where [X] is greatest integer less than or equal to x) then$