If f(x)={6x−3x−2x+12sin2(x2),ifx≠0K,ifx=0 is continuous at x=0, then K=
log (5)
2log3.log2
32log3.log2
log3.log2
K=f(0)=Ltx→0f(x)=Ltx→0(3x−1)(2x−1)2sin2(x2) =Ltx→0(3x−1)(2x−1)x22sin2(x2)x2=log3.log22.14=2log3.log2