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If f(x)x2x+1dx=32logx2x+1+13tan12x13+C  

then f(x) is equal to 

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a
3x
b
3x−4
c
3x−1
d
11+x2

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detailed solution

Correct option is C

Differentiating both the sides w.r.t. x , we get f(x)x2−x+1=322x−1x2−x+1+1311+(2x-13)223=322x−1x2−x+1+12x2−x+1⇒f(x)=3x−1


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