If ∫f(x)x2−x+1dx=32logx2−x+1+13tan−12x−13+C
then f(x) is equal to
3x
3x−4
3x−1
11+x2
Differentiating both the sides w.r.t. x , we get
f(x)x2−x+1=322x−1x2−x+1+1311+(2x-13)223
=322x−1x2−x+1+12x2−x+1⇒f(x)=3x−1