If f(x)=|x|−3, x<1|x−2|+a, x≥1 and g(x)=2−|x| , x<2sgn(x)−b, x≥2 and h(x)=f(x)+g(x) is continuous at exactly one point then which of the following value of a and b are not possible
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a
a=−3, b=0
b
a=2, b=1
c
a=2, b=0
d
None of these
answer is C.
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Detailed Solution
f(x) is continuous for all x if it is continuous atx=1 for which |1|−3=|1−2|+a or a=−3 g(x) is continuous for all x if its is continuous at x=2 for which 2−|2|=sgn(2)−b=1−b or b=1. Thus, f(x)+g(x) is continuous for all x if a=−3, b=1 Hence, f(x) is discontinuous at exactly one point for option (A).For option (B) f(x) is discontinuous at one point and for option (C) f(x) is discontinuous at two points.