First slide

Functions (XII)

Question

$If f (x) = \{\begin{array}{cl} 2 - x; & x < 0 \\ x^{2} - 4 x + 2; & x \geq 0 \end{array}, then the value of f (f (f (1))) i s$

Easy

A

$> 0$
B

$< 0$
C

$= 0$
D

does not exist

Solution

$f (1) = 1^{2} - 4 + 2 = - 1 \Rightarrow f (f (1)) = f (- 1) = 2 - (- 1) = 3 \Rightarrow f ((f (f (1)))) = f (3) = 3^{2} - 4 \cdot 3 + 2 = - 1 < 0$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App