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If then is
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a
ex+2log3x−43x+4+c
b
−83log|1−x|+23x+c
c
83log|1−x|+x3+c
d
e[(3x−4)(3x+4)]−x22−2x+c
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Correct option is B
Put x=3t−43t+4=1−83t+4,dx=24(3t+4)2dtNow ∫f(x)dx=∫f3t−43t+424(3t+4)2dt=∫t+2(3t+4)2(24)dt=8∫3t+4+2(3t+4)2dt=8∫13t+4+2(3t+4)2dt=83log|3t+4|−2383t+4+C1=83log81−x−23(1−x)+C1=−83log|1−x|+23x+CSimilar Questions
The value of is equal to
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