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If f(x)=x|x| , then for any real number a and  b 

with a<b, the value of abf(x)dx equals

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a
13|b|3−|a|3
b
13b3−a3
c
13a3+b3
d
13a3−b3

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detailed solution

Correct option is A

∫ab f(x)dx=∫ab x|x|dx=∫ab −x2dxb<0∫a0 −x2dx+∫0b x2dx,a<0


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