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$If f (x) = \frac{1}{x^{2} - 17 x + 66} then f (\frac{2}{x - 2}) is discontinuous at x is equal to$

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2,73,2511

2,83,2411

2,73,2411

2,6,9

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detailed solution

Correct option is C

Let t=2x−2 is discontinuous at x=2f(t)=1t2−17t+66=1(t−11)(t−6) is discontinuous at t=6,11∴2x−2=6,11⇒x=73,2411

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If f(x)=1x2−17x+66 then f2x−2 is discontinuous at x is equal to

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$If f (x) = \frac{1}{x^{2} - 17 x + 66} then f (\frac{2}{x - 2}) is discontinuous at x is equal to$