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$If f (x) = 2 x^{3} + 7 x - 5, then f^{- 1} (4) is$

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Correct option is A

Note that f is bijective, hence f−1 exist when y=4 , 2x3+7x−9=0⇒2x2(x−1)+2x(x−1)+9(x−1)=⇒(x−1)2x2+2x+9=0⇒x=1 only as 2x2+2x+9=0 has no other real roots ,since ∆<0 ⇒f1=4 ⇒f-14=1

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If f(x)=2x3+7x−5 , then f−1(4) is

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$If f (x) = 2 x^{3} + 7 x - 5, then f^{- 1} (4) is$