If f(x)=x1+x2, then ( fofof )(x)=
3x1+x2
x1+3x2
3x1−x2
None of these
fx=x1+x2 ⇒ffx=fx1+x2=x1+x21+x21+x2=x2x2+1
⇒fffx= fx2x2+1=x2x2+11+x22x2+1=x3x2+1