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Q.

If f(x)=x2−10x+25x2−7x+10 for x≠5 and f is continuous at x=5 then f(5) =

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a

0

b

5

c

10

d

25

answer is A.

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Detailed Solution

f(5)=Ltx→5f(x)=Ltx→5x2−10x+25x2−7x+10= Ltx→5(x−5)2(x−2)(x−5)=0

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