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Q.

If f(x)=∫7x+x7−17xlog⁡7+7x6dx then f(1)−f(0)

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a

3

b

3 log 2

c

2 log 3

d

2

answer is B.

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Detailed Solution

f(x)=∫7xlog7+7x6x7+7xdx Let 7x+x7=t⇒7xlog⁡7+7x6dx=dtf(x)=∫   1tdt=log⁡t+cf(x)=log⁡x7+7x+cf(1)−f(0)=log(8)−0=3log2
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