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$If f (x) = \int {(7^{x} + x^{7})}^{- 1} (7^{x} \log 7 + 7 x^{6}) d x then f (1) - f (0)$

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Correct option is B

f(x)=∫7xlog7+7x6x7+7xdx Let 7x+x7=t⇒7xlog⁡7+7x6dx=dtf(x)=∫ 1tdt=log⁡t+cf(x)=log⁡x7+7x+cf(1)−f(0)=log(8)−0=3log2

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If f(x)=∫7x+x7−17xlog⁡7+7x6dx then f(1)−f(0)

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$If f (x) = \int {(7^{x} + x^{7})}^{- 1} (7^{x} \log 7 + 7 x^{6}) d x then f (1) - f (0)$