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 If f(x)=5x8+7x6x2+1+2x72dx, and f(0)=0, then the value  of f(1) is 

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a
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c
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d
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detailed solution

Correct option is B

f(x)=∫5x8+7x6x142+1x7+1x52dx=∫5x6+7x82+1x7+1x52dx Put, 2+1x7+1x5=t⇒ f(x)=−∫dtt2=1t+c=x72x7+x2+1+cf(0)=0⇒ c=0⇒ f(x)=x72x7+x2+1⇒ f(1)=14


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