First slide
Theory of equations
Question

 If f(x)=x2+3x+2x27x+a and g(x)=x2x12x2+5x+b, then the values of a and b , if (x+1)(x4)  is HCF of f(x) and g(x), are 

Moderate
Solution

f(x)=x2+3x+2x27x+a  =(x+1)(x+2)x27x+a

f(x) is divisible by (x+1)(x-4)

 x27x+a is divisible by x4  a=12

similarly g(x)=x2x12x2+5x+b

                      =(x-4)(x+3)(x2+5x+b)

x2+5x+b is divisible by x+1

b=4

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