If fx=8x-4x-2x+1x2, x>0exsinx+πx+λ ln 4, x≤0 is continuous at x = 0, then the value of λ is
4loge2
2loge2
loge2
none of these
f0=0+0+λ ln 4=λln4 1 R.H.L. =limx→0+ fx= limh→0 f0+h =limh→0 8h-4h-2h+1h2 =limh→0 4h-12h-1h.h = limh→0 4h-1h.. 2h-1h = ln 4 ln 2 2∴ f0=R.H.L.∴ λ=ln2