First slide
Introduction to Determinants
Question

If f(x)=33x3x2+2a23x3x2+2a23x3+6a2x3x2+2a23x3+6a2x3x4+12a2x2+2a4, then

Moderate
Solution

Applying C3C3xC2,C2C2xC1, we obtain

Δ(x)=302a23x2a24a2x3x2+2a24a2x6a2x2+2a4

      =4a43013x12x3x2+2a22x3x2+a2

Applying C3C3xC2, we get

Δ(x)=4a43013x1x3x2+2a22xx2+2a2

Applying C1C13C3, we get

Δ(x)=4a400101x4a22xx2+2a2=16a6

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