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If f(x)=(1+x)17(1+x)19(1+x)23(1+x)23(1+x)29(1+x)34(1+x)41(1+x)43(1+x)47=A+Bx+Cx2+.then A is equal to ……

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detailed solution

Correct option is C

Since,f(x)=(1+x)17(1+x)23(1+x)411(1+x)2(1+x)61(1+x)6(1+x)111(1+x)2(1+x)6=0                                                                                                      Since, R1 and R3 are identicalA=0


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