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If $f (x + y) = f (x y) \forall x, y ε R,$ and $f (2013)$ = 2013, then f(– 2013) equals

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a

2013

b

0

c

-2013

d

none of these

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detailed solution

Correct option is A

f(2013)=f(2013+0)=f[(2013(0)]=f(0)⇒ f(0) = 2013Also, f(– 2013)=f(– 2013+0)=f(0)=2013.It can also be seen that f is a constant function.

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