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If $f (y) = \frac{y}{\sqrt{(1 - y^{2})}}, g (y) = \frac{y}{\sqrt{(1 + y^{2})}},$ then (fog)(y) is equal to

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y1-y2

y1+y2

1-y21-y2

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detailed solution

Correct option is C

f(y)=y1-y2,g(y)=y1+y2and fogy=fgy=fy1+y2=y1+y21-y21+y2=y1+y211+y2=y

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If f(y)=y1-y2,g(y)=y1+y2,then (fog)(y) is equal to

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If $f (y) = \frac{y}{\sqrt{(1 - y^{2})}}, g (y) = \frac{y}{\sqrt{(1 + y^{2})}},$ then (fog)(y) is equal to