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a
|1+α+α2+α3+α4|=0
b
|1+α+α2+α3|=1
c
|1+α+α2|=2cosπ5
d
|1+α|=2cosπ10
answer is Û.
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Detailed Solution
we have α=cos2π5+isin2π5 and 1+α+α2+α3+α4=0 ∴|1+α+α2+α3|=|−α4|=|α4|=1 Also, |1+α+α2|=|−α3(1+α)|=|1+α|...................(i) =|1+cos2π5+isin2π5| =|2cosπ5(cosπ5+isinπ5)|=2cosπ5 Again from (i), |1+α|=|1+α+α2|=2cosπ5