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If the first, second and the last terms of an A.P. are a, b, c respectively, then the sum of the A.P. is

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a
(a+b)(a+c−2b)2(b−a)
b
(b+c)(a+b−2c)2(b−a)
c
(a+c)(b+c−2a)2(b−a)
d
none of these

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detailed solution

Correct option is C

Let there be n terms in the A.P. Then, c=a+(n−1)(b−a)                                [∵d=b−a]⇒ n=b+c−2ab−a∴ sum of n terms =n2(a+c)=(b+c−2a)(a+c)2(b−a)


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