Questions
If the first, second and the last terms of an A.P. are a, b, c respectively, then the sum is
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a
(a+b)(a+c−2b)2(b−a)
b
(b+c)(a+b−2c)2(b−a)
c
(a+c)(b+c−2a)2(b−a)
d
None of these
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Correct option is C
We have, first term = a, ∴T1 = aSecond term = b, ∴T2 = bThen common difference d = T2 – T1 = b – aAlso, last term = c.⇒ c=a+(n−1)d⇒n=c−a+dd.⇒ n=(b+c−2a)(b−a) (∵d=b−a)∴ Sum of n terms Sn=n2(a+l)=(b+c−2a)(a+c)2(b−a)Similar Questions
If the sum of first terms of an is , then the sum of squares of these terms is
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