If the focus of the parabola x2−ky+3=0 is (0,z),then the values of k is (are)

The given Parabola isx2−ky+3=0or x2=ky−3kLet x=Y,y−3k=XThen the Parabola isY2:kXwhose focus is (0, k/4).Therefore, the focus of x2=ky−3k is0,3k+k4≡(0,2)∴ 3k+k4=2or 12+k2=8kor k2 - 8K+ 12=0or (k-6)(k-2)= 0or k = 2 ,6