Questions
If the foot of the perpendicular from the origin to straight line is at the point Then the equation of the line is
a
3x-4y=25
b
3x-4y+25=0
c
4x+3y-25=0
d
4x-3y+25=0
detailed solution
Correct option is A
Let O(0,0) be the origin and P(3, -4) be the given point. Slope of OP=−43 Slope of the required line =34Clearly, required line passes through P( 3, - 4) and is perpendicular to OP. So, its equation is y+4=34(x−3) or, 3x−4y−25=0The equation of a line passing through two points (x1, y1) and (x2, Y2), is y−y1=y2−y1x2−x1x−x1Talk to our academic expert!
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