Questions
If from the origin a chord is drawn to the circle then the locus of the mid point of the chord has equation
a
x2+y2+x+y=0
b
x2+y2+2x+y=0
c
x2+y2−x=0
d
x2+y2−2x+y=0
detailed solution
Correct option is C
Let (h, k) be the mid point of the chord drawn through the origin. Then the equation of the chord is hx+ky−(x+h)=h2+k2−2h [Using : T=S']This passes through (0, 0). ∴ −h=h2+k2−2h⇒h2+k2−h=0Hence, the locus of (h,k) is x2+y2−x=0Talk to our academic expert!
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