First slide

Functions (XII)

Question

$If a function f : [2, \infty) \to B defined by f (x) = x^{2} - 4 x + 5 is a bijection, then B is equal to$

Easy

A

$R$
B

$[1, \infty)$
C

$[4, \infty)$
D

$[5, \infty)$

Solution

$f (x) = x^{2} - 4 x + 5 = {(x - 2)}^{2} + 1 \geq 1 f o r a l l x \in [2, \infty)$
$R a n g e o f f (x) = [1, \infty) = C o d o m a i n B, \sin c e f i s o n t o$

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