If the function f:2,∞→−1,∞ is defined by f(x)=x2−4x+3 then f−1(x)=
2−x+1
2+x+1
2−x+15
2+x+15
Let f(x) = y
x2-4x+3=y x-22=y+1 x-2=y+1 x=2+y+1