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Questions  

If the function f:1,1, is defined by f(x)=2xx1 then f1(x) is

a
12x(x−1)
b
121+1+4log2x
c
121−1+4log2x
d
121±1+4log2x

detailed solution

Correct option is B

y=2x(y−1)⇒xx−1=log2y⇒x2−x−log2y=0∴ x=1±1+4log2y2∴ f−1(x)=121+1+4log2y  ∵x≥1

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