If the function f:1,∞→1,∞ is defined by f(x)=2xx−1 then f−1(x) is
12x(x−1)
121+1+4log2x
121−1+4log2x
121±1+4log2x
y=2x(y−1)⇒xx−1=log2y
⇒x2−x−log2y=0
∴ x=1±1+4log2y2
∴ f−1(x)=121+1+4log2y ∵x≥1