If a function f:R→R satisfies (x-y)f(x+y)-(x+y)f(x-y)=2x2y-y3∀x,y∈R and f(1)=2, then
f(x) must be polynomial function
f(3) = 12
f(0) = 0
f(x) may not be differentiable
(A,B,C)
(x−y)f(x+y)−(x+y)f(x−y)=2yx−y(x+y) Let x−y=u;x+y=vuf(v)−vf(u)=uv(v−u)f(v)v−f(u)u=v−u
f(v)v−v=f(u)u−u= constant Let f(x)x−x=λ⇒f(x)=λx+x2f(1)=2λ+1=2⇒λ=1 f(x)=x2+x