If function f(x)  is differentiable at x=a then limx→a x2f(a)−a2f(x)x−a is

For x≠a,x2f(a)−a2f(x)x−a=x2−a2f(a)+a2(f(a)−f(x)x−a=(x+a)f(a)−a2f(x)−f(a)x−aTherefore,   limx→a x2f(a)−a2f(x)x−a=2af(a)−a2f′(a)