First slide

Algebra of real valued functions

Question

If function f:N $\to$ N is defined by f(x)= $\sqrt{x}$ , then $\frac{f (25)}{f (16) + f (1)}$ is equal to

Easy

A

$\frac{5}{6}$
B

$\frac{5}{7}$
C

$\frac{5}{3}$
D

1

Solution

Given,f(x)= $\sqrt{x}$
$∴ f (25) = \sqrt{25} = 5 \Rightarrow f (16) = \sqrt{16} = 4 \Rightarrow f (1) = \sqrt{1} = 1 N o w, \frac{f (25)}{f (16) + f (1)} = \frac{5}{4 + 1} = 1$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App