If f(x) is areal-valued function defined as fx=ln1-sinx, then the graph of f(x) is
symmetric about the line x=π
symmetric about the y-axis
symmetric about the tine x=π2
symmetric about the origin
fπ2-x=ln1-cosx and fπ2+x=ln1-cosx Thus, fπ2+x=fπ2-x Thus, fx is symmetrical about line x=π2.