Q.
If f(x) is areal-valued function defined as fx=ln1-sinx, then the graph of f(x) is
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a
symmetric about the line x=π
b
symmetric about the y-axis
c
symmetric about the tine x=π2
d
symmetric about the origin
answer is C.
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Detailed Solution
fπ2-x=ln1-cosx and fπ2+x=ln1-cosx Thus, fπ2+x=fπ2-x Thus, fx is symmetrical about line x=π2.
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