If f(x)=cos (loge x),then the value of f(x)f(y)-12f(xy)+f(xy)is
-1
½
-2
none of these
Given,f(x)=cos(logex)
∴f(x)f(y)-12{f(xy)+f(xy)}
=cos (logx)cos (logy)-12{cos log xy+cos log (xy)}
=cos (logx)cos( logy)-12{cos (logx-logy)+cos (logx+log y)
=cos (logx)cos (logy)-12{2cos (logx )cos (log y)}=0