If g : [−2,2]→R, where f(x)=x3+tan⁡x+x2+1P is an odd function, then the value of parametric P, where [.] denotes the greatest integer function, is

g(x)=x3+tan⁡x+x2+1Por  g(−x)=(−x)3+tan⁡(−x)+(−x)2+1P=−x3−tan⁡x+x2+1Por  g(x)+g(−x)=0Because g(x) is a odd function,−x3−tan⁡x+x2+1P+−x3−tan⁡x+x2+1P=0or  2x2+1P=0 or 0≤x2+1P<1Now, x∈[−2, 2]∴ 0≤5P<1 or P>5