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a
g(x)f(x)−g(x)f′(x)+C
b
g(x)f′(x)+C
c
g(x)f(x)+C
d
g(x)f2(x)+C
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Correct option is C
∫g(x)f(x)+f'(x)∣dx=∫g(x)f(x)dx+∫g(x)f′(x)dx integration by parts=f(x)∫g(x)dx−∫f′(x)∫g(x)dxdx+∫g(x)f′(x)dx =f(x)g(x)−∫g(x)f′(x)dx+∫g(x)f′(x)dx+C ∵∫g(x)dx=g(x) =f(x)g(x)+CSimilar Questions
is equal to
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