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If $g (x) = \int_{0}^{x} \cos^{4} t dt$ then $g (x + π)$ equals

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detailed solution

Correct option is A

g(x+π)=∫0x+π cos4⁡ t dt=∫0π cos4⁡ t dt+∫πx+π cos4⁡ t dt=g(π)+I1In I1, put t=π+u, so that I1=∫0x cos4⁡ (π+u)du=∫0x cos4⁡ udu=g(x).

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If g(x)=∫0x cos4⁡ t dt then g(x+π) equals

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If $g (x) = \int_{0}^{x} \cos^{4} t dt$ then $g (x + π)$ equals